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f is derivable at x = 1 f is not derivable at x = 1 f is derivable at x = 1 None of the above

Answer :

BSolution :

The given function is `f(x) ={ {:(0,0le x lt1),(1,1lex lt 1):}` <br> Now , LHD `=underset(xto1^(-))lim(f(x)-f(1))/(x-1) = underset(x to 1^(-))lim(0-1)/(x-1) `, which does not exist . <br> `because ` LHD does not exist . <br> ` rArr r ` is not derivable at x = 1 .